1 Log in Join now 1 Log in Join now Ask your question 35aryan Mathematics High School 5 pts Answered X^33x^2y3xy^2y^3Typo/misspeak around 4 minutes 369=27Multivariable Calculus Find all local maxima/minima and saddle points for the function f(x,y) = x^3 3xy y^3 WThe given expression to be factorized is x 3 − 1 y 3 3xy This can be written in the form x 3 − 1 y 3 3xy = `(x)^2 (1)^3 (y)^3 3 (x)(1)(y)`
If U X Log Xy Wherex3 Y3 3xy 1 Then Du Dx Is Equal Toa B C D Correct Answer Is Option A Can You Explain This Answer Edurev Electronics And Communication Engineering Ece
X(x^3-y^3)+3xy(x-y) solution
X(x^3-y^3)+3xy(x-y) solution-To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW `(x^33xy^2)dx=(y^33x^2y)dy`Calculus Find dy/dx x^3y^3=3xy^2 x3 y3 = 3xy2 x 3 y 3 = 3 x y 2 Differentiate both sides of the equation d dx (x3 y3) = d dx(3xy2) d d x ( x 3 y 3) = d d x ( 3 x y 2) Differentiate the left side of the equation Tap for more steps
Answer to Let f(x, y) = 3xy x^3 y^3 Find all critical points of f and state whether each is a local maximum, local minimum, or saddle pointSolution Steps x ^ { 3 } 3 x ^ { 2 } y 3 x y ^ { 2 } y ^ { 3 } x 3 3 x 2 y 3 x y 2 y 3 Use the binomial cube formula, a^ {3}3a^ {2}b3ab^ {2}b^ {3}=\left (ab\right)^ {3}, where a=x and b=y Use the binomial cube formula, a 3 3 a 2 b 3 a b 2 b 3 = ( a b) 3, where a = x and b = y \left (xy\right)^ {3}Xy x y x y y 2 132 01 1 24 y xy x y But 2 132 10 24 y xy ,since we're adding two squares, for all values of x and y, taking the value 0 only when xy 1 It follows that the graphs of xxyy33 31 and x y 1 are the same except for the inclusion of the point 1, 1 in the former If you replace 2 132 1 24 y xy
Solution for find the extrema for f(x,y)= x^3 y^3 6xy Q Find any intercepts and test for symmetryThen sketch the graph of the equation y = 8/x A To find the x intercept, we plug y=0 and find x So there is no xintercepts To find yintercept weThis means that the polynomial $x^3y^33xy1$ is divisible by $xy1$ Performing long division you get the following factorization $$x^3y^33xy1= (xy1)(x^2xyy^2xy1)$$ so the problem becomes proving that $(x;y)=(1;1)$ is the only zero for $$x^2xyy^2xy1=0$$ Call $X=x1$ and $Y=y1$Solution for x^3y^3=3xy equation Simplifying x 3 y 3 = 3xy Solving x 3 y 3 = 3xy Solving for variable 'x' Reorder the terms 3xy x 3 y 3 = 3xy 3xy Combine like terms 3xy 3xy = 0 3xy x 3 y 3 = 0 The solution to this equation could not be determined
Solution for if u=x log xy where x3y33xy=1 find du/dx Q A rectangle has a length of 7 inches and a width of 8 inches, whose sides are changingThe length i A Given A rectangle has a length of 7 inches and a width of 8 inches, whose sides are changingThe leAnswer x3 y3 3xy = 1 x3 y3 (−1)3 −3xy(−1)= 0 using the identity a3 b3 c3 −3abc= (abc)(a2 b2 c2 −ab−bc−ca) ⇒ (xy−1)(x2 y2 1−xy y x) = 0 → (xy −1)(2x2 2y2 2−2xy2y2x)= 0 → (xy −1)(x−y)2 (x1)2 (y 1)2 =0 ⇒ xy = 1 or x= y = −1 ⇒ a line xy−1 = 0 or a point (−1,−1) = (x y z)x 2 y 2 – 2xy y 2 z 22yz z 2 x 2 – 2zx = (x y z)(xy) 2 (yz) 2 (zx) 2 Ex 25 Class 9 Maths Question 13 If x y z = 0, show that x 3 y 3 z 3 = 3xyz Solution We know that, x 3 y 3 z 3 – 3xyz = (x y z)(x 2 y 2 z 2 – xy – yzzx) = 0(x 2 y 2 z 2 – xy yzzx) (∵ x y z = 0
Find the extreme values of the function x 3 y 3 – 3xy differential calculus answered by Taniska (645k points) selected by Vikash Kumar Best answer Let f (x, y) = x 3 y 3 – 3xy We have f x = 3x 2 – 3y f y = 3y 2 – 3x Now f x = 0 and f y A unique platform where students can interact withX^33x^2y3xy^2y^3 ———————————— X^3y^3 Get the answers you need, now!TCS Numerical Ability Question Solution what is the max value of x3y33xy,when xy=8?
Changes made to your input should not affect the solution (1) "y3" was replaced by "y^3" 1 more similar replacement(s) Step 1 Equation at the end of step 1 (x•((x 3)(y 3)))3xy•(xy) Step 2 Trying to factor as a Difference of Cubes 21 Factoring x 3y 3 Theory A difference of two perfect cubes, a 3 b 3 can be factored intoElaborating x 3 y 3 using identity a 3 b 3 = (a b) (a 2 ab b 2 ) = x ( x y) (x 2 xy y 2 ) 3xy (x y ) Taking common x ( x y ) in both the terms = x ( x y) {x 2 xy y 2 3y} ∴ x (x 3 y 3 ) 3xy ( x y) = x ( x y ) (x 2 xy y 2 3y) Concept Algebraic Expressions Report ErrorQuestion The equation x3 3xy y3 = 1 is solved in integers Find the possible values of xy Found 3 solutions by Alan3354, Edwin McCravy, richard1234
Calculus Find dy/dx x^3y^3=3x^2y3xy^2 x3 y3 = 3x2y 3xy2 x 3 − y 3 = 3 x 2 y − 3 x y 2 Differentiate both sides of the equation d dx (x3 y3) = d dx(3x2y 3xy2) d d x ( x 3 − y 3) = d d x ( 3 x 2 y − 3 x y 2) Differentiate the left side of the equation Tap for more stepsSimple and best practice solution for y(2xy1)dxx(3x4y3)dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it 24,548 #2 bedigursimran said The folium of Descartes has the graph shown below in Figure 1, the Cartesian equation is x^3 y^3 = 3xy Use the substitution y/x = t to find the parametric equation of the folium View attachment 8486 The problem that I have with it is understanding how to go about doing it
Using the identity `x^3 y^3 z^3 3xy\z` `= (x y z)(x^2 y^2 z^2 xy – yz – xz)` We get `(3x y z)(3x)^2 y^2 z^2 3xy – yz – 3xz` `= (3x y z)(9x^2 y^2 z^3 3xySolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreSolution for 3xy (xy)= equation Simplifying 3xy (x y) = 0 (x * 3xy y * 3xy) = 0 Reorder the terms (3xy 2 3x 2 y) = 0 (3xy 2 3x 2 y) = 0 Solving 3xy 2 3x 2 y = 0 Solving for variable 'x' Factor out the Greatest Common Factor (GCF), '3xy' 3xy (y x) = 0 Ignore the factor 3
Click here👆to get an answer to your question ️ Factorise x^3 2x^2y 3xy^2 6y^3 Join / Login maths Factorise x 3 − 2 x 2 y 3 x y 2 − 6 y 3 Answer Given x 3 − 2 x 2 y 3 x y 2 − 6 y 3 By taking x 2 as common in the first two term and 3 y 2 as common in the second two term x 3 Explanation differentiate implicitly with respect to x The product rule has to be used on the right side 3x2 3y2 dy dx = 3x dy dx 3y ⇒ 3y2 dy dx −3x dy dx = 3y − 3x2 ⇒ dy dx (3y2 −3x) = 3(y − x2) ⇒ dy dx = 3(y − x2) 3(y2 − x) = y − x2 y2 − x Answer linkThe differential with respect to x of x 3 = 3x 2 The differential with respect to x of y 3 = 3y 2 dy/dx The differential with respect to x of 3xy =3y 3xdy/dx (By Chain Rule u = 3x v = y) The differential with respect to x of 6 = 0 As such, we can form the equation 0 = 3x 2 3y 2 dy/dx 3y
The function F(x, y) = x 3 y 3 3xy 4 First order partial derivatives f x (x, y) = 3x 2 3y f y (x, y) = 3y 2 3x Second order partial derivatives F xx (x, y) = 6x F yy (x, y) = 6y F xy (x, y) = 3 Step 2 The critical points satisfy the equations f x (x,y) = 0 and f y (x,y) = 0 So solve the following equations F x = 0 and F yTiger Powers x^3y^33xy(xy) indicate repeated multiplication of the same factor The base (bottom number) of a power indictates the factor being multiplied and Put x y = u, x − y = v;
= x(x – y) (x^2 xy y^2 3y) = x(x – y) (x^2 xy y^2 3y)$$\Rightarrow x^3y^31=3xy$$ which is the given equation Therefore, $$xy=t$$ $$\Rightarrow xy=1$$Let f(x, y)= x^3y^3 3xy (a) Find the critical points of f (b) Classify each critical point in part (a) as either a local maximum, local minimum, or saddle point Question Let f(x, y)= x^3y^3 3xy (a) Find the critical points of f (b) Classify each critical point in part (a) as either a local maximum, local minimum, or saddle point
Solution Question 16 Give possible expression for the length and breadth of the rectangle having 35y 2 13y – 12 as its area Solution Area of a rectangle = 35y 2 13y – 12 = 35y 2 28y 15y 12 (i) If length = 5y 4, then breadth = 7y – 3 (ii) # (x^3 y^3)=3xy^2 dy/dx # We can rearrange this Differential Equation as follows # 3 \ dy/dx = (x^3 y^3)/(xy^2) # # " " = x^3/(xy^2) y^3/(xy^2) # # " " = x^2/y^2 y/x # # " " = (x/y)^2 y/x # This would lead us to try a substitution, Let # v = y/x => y=vx# Then # dy/dx = v xCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge and
Mathx^3 /mathmath y^3/math = 3xy d/dx(mathx^3 /mathmath y^3/math) = d/dx(3xy) 3mathx^2/math 3mathy^2/math * dy/dx = 3y 3x * dy/dx 3mathx^2/math 3mathy^2/math * dy/dx 3mathx^2 /math 3x * dy/dx = 3y 3 Find an answer to your question factorise x^33x^2y3xy^2y^3 kendallsnyder1 kendallsnyder1 Mathematics College answered Factorise x^33x^2y3xy^2y^3 1 See answer kendallsnyder1 is waiting for your help Add your answer and earn points144 B256 C8192 D102
If x y1=0,prove that x^3y^33xy=1Then u and v are integers of the same parity In the new variables the equation becomes 1 8 ( 6 u 2 v 2 v 3) = 1 4 ( u 2 − v 2) 61 , which can be written as 27 u 2 ( 3 v 2) 2 = 6584 3 v − 1 u = x 3 y 3 3xy 2 ∴ u is a homogeneous function in x and y of degree 3 1 answer Let u = x^2 y^3 cos(x/y) By using Euler's theorem show that x∂u/∂x y∂u/∂y asked in Applications of Differentiation by A unique platform where students can interact with teachers/experts/students to get solutions to their
0 View Full Answer Vishnu Rai, added an answer, on 25/5/17 Vishnu Rai answered this Please find this answer Was this answer helpful?Answer to Find the critical points of the function f(x,y) = 4 x^3 y^3 3xy and classify them as local maximum or minimum or saddle pointsSOLUTION u = x log xy x 3 y 3 3xy = 1 By using total differentiation concept, \(du = \left( {\frac{{\partial u}}{{\partial x}}} \right)dx \left( {\frac
Simple and best practice solution for 3(Xy)=y equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it x(x^3 – y^3) 3xy(x – y) = x(x – y) (x^2 xy y^2) 3xy(x – y) Taking x(x – y) as a common factor;Math(x^3y^3)dx 3xy^2dy=0/math math3xy^2dy = (x^3y^3)dx/math math3\frac{dy}{dx} = \frac{x^3y^3}{xy^2}/math math3\frac{dy}{dx} = \frac{x^2}{y^2
X^33xyy^3=0 WolframAlpha Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge and capabilities to the broadest possible range ofFor the differential equation, x^2y" 3xy' 3y = x^3 (a) (Do Not Find the General Solution Use the transformation x = e^t, dy/dx = 1/x dy/dt and d^2y/dx^2 = 1/x^2 (d^2y/dt^2 dy/dt) to convert it to a 2nd order differential equation with constant coefficients) (Do Not Find the General Solution) (b) Find the general solution of x^2y" 3xy' 3y = x^3 using the method of Variation of
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